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6x^2-3=555
We move all terms to the left:
6x^2-3-(555)=0
We add all the numbers together, and all the variables
6x^2-558=0
a = 6; b = 0; c = -558;
Δ = b2-4ac
Δ = 02-4·6·(-558)
Δ = 13392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13392}=\sqrt{144*93}=\sqrt{144}*\sqrt{93}=12\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{93}}{2*6}=\frac{0-12\sqrt{93}}{12} =-\frac{12\sqrt{93}}{12} =-\sqrt{93} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{93}}{2*6}=\frac{0+12\sqrt{93}}{12} =\frac{12\sqrt{93}}{12} =\sqrt{93} $
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